Hi, I dont udnerstand AND right.
My funny ASM-BOOK i consulted, cant explain me axactly for what I can use that command.

Can someone give me an axample where I need this operand ?
And give a little example ?

Thx
Posted on 2003-03-26 13:53:25 by Forginforcer
And and the other logical instructions are useful for bit masking. This means performing an operation on a certain number of bits in a data object while leaving the other bits unmodified.

You can use the and instruction to convert an lower case character to an upper case one. The fifth bit of the character determines whether it is upper case or lowercase. If
bit 5 is 1 the character is lowercase and 0 means it is Upper case. So to convert a lower case character to upper case all we have to do it set bit 5 to 0. Here is an example.

mov al 'a'
and al 0011011111

The and instruction comapres bit x of 11011111 with bit x of al. If both bits are 1 the result is one. If one of the bits is zero the result is zero. The result is stored in al. The bits in al determine the result if the other operand is 1. If the other operand is 1 , the result is 1 if it is 0 the result is zero. So if the other operand is 1 the bits are not changed. When we get to bit 5 , the result is 0 because one of the operands is 0.
Posted on 2003-03-26 14:28:51 by Odyssey
Trying to display the hex value of a number would be another example where you could use the AND mnemonic.

;assuming the number in AX

rol al,4 ;get the high nibble (4 bits) in the lower nibble of AX
push ax
and al,0fh ;this will keep only the lower 4 bits
cmp al,"9"
jbe @F
add al,7 ;converts to the letters A-F if the nibble >9
@@:
..... ;store or display the content of AL
pop ax ;retrieve the number being processed
....

Repeat the above 3 more times and you will have obtained the ASCII hex value of the number in AX. For a 32-bit number, you would do it a total of 8 times, using EAX instead of AX. For bytes, do it only twice in AL.

Raymond
Posted on 2003-03-26 15:29:07 by Raymond
One use for AND is for clearing bits.

Let's say you have four bits 0111, and you want to clear the second bit from the right (to produce 0101).

The bit mask that shows the bit position is

0010

Complement it to this:

1101

Then AND it:

0111 Original bits