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Newbie question =p
i cant seem to solve this easy problem... perhaps im too tired from work :) Anyway, here is want i want to do:

(This is sorta like a converter)

editbox1 contains Win32
editbox2 is empty

1. Get "W" from string Win32, convert W to decimal, add 100, convert it to hex and add it to a buffer.

2 Get "i" from string Win32, convert i to decimal, add 100, convert it to hex and add it to a buffer. (The buffer now contains the hex from #1 and #2 and so on...)

3 like above

4. like above

5. like above

6 SetDlgItemText the buffer to the empty editbox...

Thanks in advance
Posted on 2003-10-29 06:11:04 by Ni?o
Newbie question =p
Something like 


.data

buffer db 64 dup (?)

.code

...

mov esi, offset buffer

mov edi, esi

invoke GetDlgItemText, hdlg, ID1, esi, 64

@@:

lodsb

test al, al

jz _out

add al, 100

stosb

jmp @B

_out:

invoke SetDlgItemText, hdlg,ID2, offset buffer

?
PS:Untested.
Posted on 2003-10-29 06:51:06 by roticv
Newbie question =p
doesnt work in a way :( i need the result in the editbox in hex format
Posted on 2003-10-29 07:06:06 by Ni?o
Newbie question =p
hmmm i found it only problem is when i convert i get 00's... for example i get 00000048 when i only need is 48.... how do i do that?
Posted on 2003-10-29 07:30:06 by Ni?o
Newbie question =p
Try this routine for to convert to hex, wrote it sometime back to remove the 0's: 


dwtoh:

	push	eax

	push	ecx

	mov		ecx, 32

@@:

	sub		ecx, 4

	jz		@F

	mov		eax, edx

	shr		eax, cl

	or		eax, eax

	jz		@B

@@:

	mov		eax, edx

	shr		eax, cl

	and		eax, 01111y

	cmp		al, 0Ah

	sbb		al,69h

	das

	stosb

	sub		ecx, 4

	jns		@B

	mov		byte ptr[edi], 0

	pop		ecx

	pop		eax

	retn

Input in edx, or unless you want to change the code and edi for the string to be stored...
Posted on 2003-10-29 08:12:14 by roticv
Newbie question =p
Afternoon, Ni?o.

This sounds suspiciously like a Key Generator.

If you'd like to NOT have this thread closed/removed, then I think it'd be appropriate for you to mention *exactly* what you are wanting to code this for.

Cheers,
Scronty
Posted on 2003-10-29 17:31:33 by Scronty
Newbie question =p
it is somewhat like a key generator. FOR MY SHAREWARE PROGRAM. :) so i guess it wont be illegal coz its for my software, right? if still in doubt i will post a copy of my program here...

anyway i came up with this code,


Posted on 2003-10-30 22:55:07 by Ni?o
Newbie question =p
Perhaps 


mov esi,offset buffer1 

mov edi, offset buffer3

Invoke GetDlgItemText,hWin,IDC_EDT1,esi,5

mov ecx, 4

@@:

lodsb

movzx edx, al

call dwtoh

dec ecx

jnz @B

mov byte ptr[edi], 0

Invoke SetDlgItemText,hWin,IDC_EDT2,offset buffer3 

...



dwtoh:

	push	eax

	push	ecx

	mov		ecx, 32

@@:

	sub		ecx, 4

	jz		@F

	mov		eax, edx

	shr		eax, cl

	or		eax, eax

	jz		@B

@@:

	mov		eax, edx

	shr		eax, cl

	and		eax, 01111y

	cmp		al, 0Ah

	sbb		al,69h

	das

	stosb

	sub		ecx, 4

	jns		@B

	pop		ecx

	pop		eax

	retn

Not too sure though, Have yet to test it...
Posted on 2003-10-30 23:59:15 by roticv