DWORD To Octal - Forums - ASM Community

Can anybody give me an idea how i can convert an unsigned DWORD value to its equivalent Octal value which should be written onto a null-terminated string?

Posted on 2006-06-26 03:40:53 by XCHG

Re: DWORD To Octal

Try this (untested - not got time atm):

Tested it now, works fine

dw2oct proc pszStr:DWORD, val:DWORD

    push edi

    mov edi, pszStr
    mov eax, val

    mov ecx, 10
    mov , ch

@@:
    mov edx, eax
    and dl, 07h
    add dl, '0'

    mov , dl
    
    shr eax, 3
    sub ecx, 1
    jns @B

    pop edi

    ret
dw2oct endp

Ossa

Posted on 2006-06-26 06:00:53 by Ossa

Re: DWORD To Octal

Probably overkill :P :P but will use only exact number of bytes in output string, instead of the output being right aligned!!!

DwordToOctal	proc	dwNumber:DWORD, pszOutString:LPTSTR
	LOCAL	szLocal[32]:BYTE
	
	push	esi	;for the temp string
	push	edi	;for the final target
	push	eax	;for number
	push	ecx	;for counting length of string
	push	edx
	
	mov	ecx, 1
	mov	eax, dwNumber
	lea	esi, szLocal
	
	.while	eax != 0
		mov	edx, eax
		and	edx, 07h	;111b
		add	dl,'0'
		
		mov	, dl
		
		inc	esi
		inc	ecx		;counter
		shr	eax,3		;div by 8
	.endw
	
	dec	esi
	mov	edi, pszOutString
	.while	ecx != 0
		mov	al, 
		mov	, al
		
		dec	esi
		inc	edi
		dec	ecx
	.endw
	mov	byte ptr ,0
	
	pop	edx
	pop	ecx
	pop	eax
	pop	edi
	pop	esi
	
	ret

DwordToOctal endp

Posted on 2006-06-26 07:44:20 by shantanu_gadgil

Re: DWORD To Octal

Okay i got the idea and coded my own algorithm. I don not think there is any need to do any tricks with the buffer as we can use ROL to first rotate the two leftmost bits of the number and convert it to its equivalent character, and the rest of the rotates to the left can be based on 3 bits now. so 32 - 2 = 30 now the result is divisible by 3 so 10 rotates to the left, each 3 times will do the job.

Posted on 2006-06-27 02:36:23 by XCHG