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string copying
let's say i have a string and a byte buffer like that: 

myString db "ABCDEFG",0
sndString db 15 dup(0)
how to copy all the letters that are in "myString" to "sndString" so, that after every letter there is a placeholder (ASCII 32). i want "sndString" to look like this: A B C D E F G I already tried something, but it doesn't work, it crashes: 

invoke StrLen,addr myString	
mov ecx,eax
lea esi,myString
lea edi,sndString
.while ecx>0
	xor eax,eax
	lodsb
	inc esi
	stosb
	inc edi
	mov al," "
	stosb
	inc edi
.endw
Posted on 2001-04-22 04:41:00 by [SaFc0n]
string copying
hey safcon, i'm not sure but try the hex value for that space Olli
Posted on 2001-04-22 05:00:00 by Typhoon
string copying
no, that's not the problem cause i use mov al," " so the character is placed in al directly, i don't need to know if it is hex or dec. that's not important in this case....
Posted on 2001-04-22 05:29:00 by [SaFc0n]
string copying
try that : 

		mov	esi,offset bfBuffer
		mov	edi,offset bfSecondBuffer
		mov	ah,' '
@@:		lodsb

		test	al,al
		jz	@f

		stosw

		jmp	@b

@@:		and	byte ptr ,0
it should work (thanks again for the link on your site to mine =), i added a link to yours =))
Posted on 2001-04-22 05:52:00 by roy
string copying
here's my version :) mov esi, offset myString lea edi, sndString mov ecx, sizeof myString .while ecx>0 mov al, byte ptr stosb ; store a letter inc esi ; next letter mov al, " " ; add a space after adding a letter stosb ; store space dec ecx ; .endw this should work too :) () - clip This message was edited by clip, on 4/22/2001 5:56:55 PM
Posted on 2001-04-22 06:20:00 by clip
string copying
ok, thank you all.
Posted on 2001-04-22 06:47:00 by [SaFc0n]