I've just read that M$ is going to support SIMD instruction set in future w2k.
What do they mean by support? :/
I use the set without any permission or support from M$.
The same was written in the past about 98 that from now on it supported MMX instructions :/?!!
What this "support" means?
Posted on 2001-08-03 07:42:06 by The Svin
I think they mean that if you've got em on your processor, the OS will use them when it can....

So if you've got SIMD, it'll waste slightly less processor power fading menus in & out :tongue:

Mirno
Posted on 2001-08-03 08:32:08 by Mirno
:)
Yes, I thoght it was something like that.
Why they then not stated that now any of their OS
supports ADD & SUB :))
Posted on 2001-08-03 08:59:15 by The Svin
They don't, they do all their programming using only and, or, xor, shifts, and conditional jumping!

Thats why all their code is so big and slow!

Mirno
Posted on 2001-08-03 09:49:59 by Mirno
Ho humm ... some of then new instruction sets require OS support
in the scheduler. MMX didn't, as it's simply aliased on the FP stack.
I think the pentium3 floating-point SIMD (SSE) requires OS support.
Try running SSE under win95, it won't work :). But since win98 already
has the necessary support, I can't see what "SIMD support" is all
about. Perhaps mirno is right, the OS using it... or perhaps they're
going to make a set of APIs to use the SIMD instructions, *g*.
Posted on 2001-08-03 15:16:36 by f0dder