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No wait I found a free FTP service...
Please read my tut and tell me what you think

You need to provide us with a link... ;)

yes, plz post it. i really need ti cause thats the part i'm struggling on. freakin geometry "Write your rule, substitute in, and solve"(Mr.Schmidt,Geometry Teacher) says that everyday but thats not helping me ;)

We are all waiting for the link for your tutorial
Where is it?
You may post it on the forum.
ok

don't tell me this guy was bs'ing:(

Nice tut. I will advice it when some beginners asks for a FPU tutorial.

Just some corrections, if you don't mind:

---

a typo:
The FPU handles internally handles everything

---

an error:
for the mantissa. So the value is calculated by
(1.0+mantissa)^exponent * (sign*-1)

should instead be:
(1.0+mantissa) * (2^exponent) * (sign*-1)

---

another typo:
There's also much confusion about whether the FPU can execute code parallel
to the FPU. This is possible, but not in the way you might think.

also, you should specify that the above comment, and what follows, is Pentium
specific.

---

on:
because the bits in the FPU and CPU flags overlap, you can just
jump on the same conditions, like JZ, JL, etc.

Error: JL won't work as expected. Maybe you better extend the info and state
that the conditions for comparisons are JE,JNE, and JA,JAE,JB,JBE.. i.e. those
of integer unsigned arithmetic. This is important to state, because it's an
"exception" to the rule you stated earlier that says "the FPU uses always signed xxx".

In fact what you write after is wrong:
<< Do remember that the FPU uses SIGNED numbers, so you have to use the signed
conditional branches, like jl, instead of the unsigned ones like jb. >>
It's the other way round.

The reason is simple: it was easier for the Intel engineers to map it this way
rather than the (considerably more complex) flags organization used by signed
integer arithmetic.

:)

I think Eoin has a nice FPU tut too. Try using the nice search tool of this board. :)

That text file will make a nice entry into my HelpPC21 ;)

Thanx!
:NaN:

it's online now